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Proof step 1 from proof div-zero-nls-01 (conclusion)

⊦ j ≠ 0 → ¬ abs(i) / abs(j) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
abs(i) / abs(j) < 0 ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs