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Proof step 6 from proof div2-add-neg (previous step)

j % 2 = 0, ~1 ≤ i0 + j, i0 < 0 ⊦ 0 < 2 ∧ 0 ≤ j, ((i0 + 1) + j) / 2 = i0 / 2 + j / 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
j % 2 = 0, ~1 ≤ i0 + j, i0 < 0, j < 0 ⊦ ((i0 + 1) + j) / 2 = i0 / 2 + j / 2

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs