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Proof step 1 from proof div2-neg-odd (conclusion)

⊦ j < 0 → (j * 2 - 1) / 2 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j < 0 ⊦ (j * 2 - 1) / 2 = j

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs