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Proof step 4 from proof div2-nls (previous step)

j < (i + j) / 2, i ≤ j, i < (i + j) / 2 ⊦ 0 < 2 ∧ 0 ≤ i + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
j < (i + j) / 2, i ≤ j, i < (i + j) / 2, i + j < 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs