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Proof step 1 from proof div2one (conclusion)

⊦ i % 2 = 1 ∧ 0 < i → i / 2 * 2 + 1 = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i % 2 = 1, 0 < i ⊦ i / 2 * 2 + 1 = i

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs