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Proof step 1 from proof diveq-neg (conclusion)

i0 * j + j0 < 0, i0 < 0, j0 ≤ 0, abs(j0) < j ⊦ (i0 * j + j0) / j = i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
abs(j0) < j, i0 * j + j0 < 0, i0 < 0, j0 ≤ 0 ⊦ (i0 * j + j0) / j = i0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs