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Proof step 14 from proof even-add (
previous step
)
j1 * 2 + j = j0 * 2 ⊦ ∃ j0. j = j0 * 2
User applied rule exists right
And obtained the following new goals
Proof step 15
:
j1 * 2 + j = j0 * 2 ⊦ j = (j0 - j1) * 2, ∃ j0. j = j0 * 2
Rule argument
pos: right 1 terms: j0 - j1 abort: F discard: F computed: F
Additional information
Used terms: j0 - j1