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Proof step 36 from proof even-add (previous step)

⊦ (i + j) % 2 = 0, j % 2 = 0, i % 2 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 37:
⊦ i % 2 ≠ 0 ↔ (∃ i0. i = 2 * i0 + 1)
Proof step 38:
⊦ (i + j) % 2 = 0, j % 2 = 0, ∀ i0. i ≠ 2 * i0 + 1

Rule argument

spec: inst: name: even-not-ex seq: ⊦ i % 2 ≠ 0 ↔ (∃ i0. i = 2 * i0 + 1) subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i