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Proof step 41 from proof even-add (previous step)

⊦ ((2 * i0 + 1) + j) % 2 = 0, ∀ i0. j ≠ 2 * i0 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
⊦ (2 + 2 * i0 + 2 * i) % 2 = 0

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2