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Proof step 1 from proof even-mult (conclusion)

⊦ (i * j) % 2 = 0 ↔ i % 2 = 0 ∨ j % 2 = 0

User applied rule case distinction

And obtained the following new goals

Proof step 2:
(i * j) % 2 = 0 ⊦ i % 2 = 0 ∨ j % 2 = 0
Proof step 15:
i % 2 = 0 ∨ j % 2 = 0 ⊦ (i * j) % 2 = 0

Rule argument

pos: right 1

Additional information