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Proof step 6 from proof even-mult (
previous step
)
(i * (2 * i0 + 1)) % 2 = 0 ⊦ i % 2 = 0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 7
:
⊦ i % 2 ≠ 0 ↔ (∃ i0. i = 2 * i0 + 1)
Proof step 8
:
(i * (2 * i0 + 1)) % 2 = 0 ⊦ ∀ i0. i ≠ 2 * i0 + 1
Rule argument
spec: inst: name: even-not-ex seq: ⊦ i % 2 ≠ 0 ↔ (∃ i0. i = 2 * i0 + 1) subst: [i] → [i] flags: rewrite, current
Additional information
Used terms: i