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Proof step 1 from proof even-or-succ-even (conclusion)

0 ≤ i ⊦ i % 2 = 0 ∨ (i + 1) % 2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i ⊦ i % 2 = 0, (i + 1) % 2 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs