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Proof step 11 from proof le-abs-numerator (previous step)
| i < 0, 0 < i / j + i, j < 0 ⊦ j = 0 |
User applied rule insert elim lemma
And obtained the following new goals
- Proof step 12:
⊦ j < 0 ∧ i < 0 → (i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ j0 ≤ 0 ∧ j < j0 ∧ 0 ≤ i0)
- Proof step 13:
i = i0 * j + j0 ∧ j0 ≤ 0 ∧ j < j0 ∧ 0 ≤ i0, i < 0, 0 < i0 + i, j < 0 ⊦ j = 0
Rule argument
spec: int-div
inst:
name: div-elim-negneg
seq: ⊦ j < 0 ∧ i < 0
→ ( i0 = i / j ∧ j0 = i % j
↔ i = i0 * j + j0 ∧ j0 ≤ 0 ∧ j < j0 ∧ 0 ≤ i0)
subst: [i, j, i0, j0] → [i, j, i0, j0]
flags: current, []Additional information
Used simplifier rules:
zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs
Used terms: i, j, i0, j0