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Proof step 18 from proof le-abs-numerator (previous step)

0 < j, 0 < i / j + i, i < 0 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 19:
i = ~ abs(i), 0 < j, 0 < i / j + i, i < 0 ⊦

Rule argument

fma: i = ~ abs(i)

Additional information

Used simplifier rules: abs-08: ⊦ i < 0 → abs(i) = ~ i; from specification int-abs%neg-02: ⊦ ~ ~ i = i; from specification int-abs Used formulas: i = ~ abs(i)