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Proof step 20 from proof le-abs-numerator (previous step)

0 < j, 0 < ~ abs(i) / j + ~ abs(i), ~ abs(i) < 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ j ≠ 0 → ~ i / j = ~(i / j)
Proof step 22:
j ≠ 0, 0 < j, 0 < ~(abs(i) / j) + ~ abs(i), ~ abs(i) < 0 ⊦

Rule argument

spec: int-div inst: name: Div-left seq: ⊦ j ≠ 0 → ~ i / j = ~(i / j) subst: [j, i] → [j, abs(i)] flags: rewrite, current

Additional information

Used terms: j, abs(i)