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Proof step 7 from proof le-abs-numerator (previous step)

0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0, ¬ i < 0 ∧ ¬ j < 0, 0 ≤ abs(i) + i / j ∧ i / j ≤ abs(i)

User applied rule cut formula

And obtained the following new goals

Proof step 8:
i < 0, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0, ¬ i < 0 ∧ ¬ j < 0, 0 ≤ abs(i) + i / j ∧ i / j ≤ abs(i)
Proof step 30:
0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ i < 0, j = 0, ¬ i < 0 ∧ ¬ j < 0, 0 ≤ abs(i) + i / j ∧ i / j ≤ abs(i)

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0