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Proof step 9 from proof le-abs-numerator (previous step)

i < 0, 0 < i / j + i, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 10:
j < 0, i < 0, 0 < i / j + i, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j = 0
Proof step 17:
i < 0, 0 < i / j + i, 0 ≤ i ∧ 0 < j → i / j * j ≤ i ⊦ j < 0, j = 0

Rule argument

fma: j < 0

Additional information

Used formulas: j < 0