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Proof step 11 from proof less-mult-div-01 (previous step)

i * i1 = i0 * (i1 + i2) + j0, 1 < i1 + i2, 0 < i2, 0 < i1, 0 ≤ j0, 0 < i0, j0 < i1 + i2, 0 < j1, 0 < i, i ≤ i0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-mult inst: name: dist-lsplit seq: ⊦ (i + i0) * j = i * j + i0 * j subst: [j, i0, i] → [i0, i2, i1] flags: rewrite

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: i0, i2, i1