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Proof step 1 from proof less-mult-div (conclusion)

⊦ 0 < i ∧ 0 < i1 ∧ 0 < j ∧ i1 < j → i * i1 / j < i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-zero-06: ⊦ i < j ∧ 0 < j ∧ 0 < i → i / j = 0;%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%zero-left: ⊦ 0 * i = 0; from specification int-mult