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Proof step 3 from proof ls-02 (previous step)

i < 0, i / i0 < j / i0, j ≤ i, 0 < i0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j < i0, i + 1 < i0, j < 0, i / i0 < j / i0, j ≤ i, 0 < i0, i < 0, i < i0, j + 1 < i0 ⊦

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1; from specification int-basic2%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs