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Proof step 6 from proof ls-02 (previous step)

i / i0 < j / i0, j ≤ i, 0 < i0 ⊦ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i / i0 < j / i0, j ≤ i, 0 < i0, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs