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Proof step 1 from proof ls-03 (conclusion)

0 < j0, 0 ≤ i, i ≤ j ⊦ i / j0 ≤ j / j0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-div inst: name: ls-01 seq: i0 ≠ 0, j0 ≠ 0, 0 ≤ i, 0 ≤ i0, i ≤ j, i0 ≤ j0 ⊦ i / j0 ≤ j / i0 subst: [i0, j, j0, i] → [j0, j, j0, i] flags: rewrite, current

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%ler: ⊦ i ≤ i; from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs Used terms: j0, j, j0, i