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Proof step 36 from proof ls-even-01 (previous step)

i % 2 = 0, j % 2 = 0, j ≤ i, i / 2 < j / 2, j ≤ ~2, j < 0, i ≤ 0 → ¬ j < i ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 37:
i % 2 = 0, j % 2 = 0, j ≤ i, i / 2 < j / 2, j ≤ ~2, j < 0 ⊦ i ≤ 0

Rule argument

pos: left 7

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs%irref: ⊦ ¬ i < i; from specification int-basic1