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Proof step 4 from proof ls-even-01 (previous step)

¬(i % 2 = 0 ∧ j % 2 = 0 ∧ 0 ≤ i ∧ 0 ≤ j), i % 2 = 0, j % 2 = 0 ⊦ i / 2 < j / 2 ↔ i < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information