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Proof step 11 from proof mod-div-zero (
previous step
)
0 ≤ i, 0 ≤ j + i % j, j < 0 ⊦ j = 0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 12
:
⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0
Proof step 13
:
0 ≤ i, 0 - i % j ≤ j, j < 0 ⊦ j = 0
Rule argument
spec: int-abs inst: name: numle-02 seq: ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0 subst: [j0, i0, j] → [i % j, j, 0] flags: rewrite
Additional information
Used terms: i % j, j, 0