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Proof step 2 from proof mod-grz-01 (previous step)

i < 0, 0 < i % j, i + 1 < i % j, abs(j) = 1 ∨ abs(j) + i ≤ 0 ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < j ∧ i < 0 → ¬ 0 < i % j
Proof step 4:
¬(0 < j ∧ i < 0), i < 0, 0 < i % j, i + 1 < i % j, abs(j) = 1 ∨ abs(j) + i ≤ 0 ⊦ j = 0

Rule argument

spec: int-div inst: name: mod-grz seq: ⊦ 0 < j ∧ i < 0 → ¬ 0 < i % j subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i