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Proof step 1 from proof mod-le-01 (conclusion)

⊦ j ≤ j0 ∧ 0 ≤ i ∧ 0 < j → i % j ≤ j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-nls-01: ⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j;%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs