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Proof step 3 from proof mod-les (previous step)

j ≤ i % j, 0 < i % j, 0 < j ⊦ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j ≤ i % j, 0 < i % j, 0 < j ⊦

Rule argument

Additional information

Used simplifier rules: mod-pos-not-neg: ⊦ 0 < i1 ∧ 0 < i % i1 → ¬ i < 0;