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Proof step 10 from proof mod-ls-same-01 (previous step)

0 ≤ i ⊦ i % j < i ↔ 0 < i ∧ (abs(j) = 1 ∨ abs(j) ≤ i), j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 11:
0 ≤ i ⊦ i = 0, i % j < i ↔ 0 < i ∧ (abs(j) = 1 ∨ abs(j) ≤ i), j = 0

Rule argument

fma: i = 0

Additional information

Used simplifier rules: mod-zero-04: j ≠ 0 ⊦ 0 % j = 0; Used formulas: i = 0