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Proof step 12 from proof mod-ls-same-01 (previous step)

0 < i ⊦ j = 0, i = 0, i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i

User applied rule cut formula

And obtained the following new goals

Proof step 13:
0 < i ⊦ j = 1, j = 0, i = 0, i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i

Rule argument

fma: j = 1

Additional information

Used simplifier rules: mod-one: ⊦ i % 1 = 0; Used formulas: j = 1