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Proof step 14 from proof mod-ls-same-01 (previous step)

0 < i ⊦ j = 1, j = 0, i = 0, i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i

User applied rule cut formula

And obtained the following new goals

Proof step 15:
abs(j) = 1, 0 < i ⊦ j = 1, j = 0, i = 0, i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i
Proof step 18:
0 < i ⊦ abs(j) = 1, j = 1, j = 0, i = 0, i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i

Rule argument

fma: abs(j) = 1

Additional information

Used formulas: abs(j) = 1