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Proof step 2 from proof mod-ls-zero (previous step)

0 < j ⊦ i % j < 0 ↔ i < 0 ∧ i % j ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < j ⊦ i % j < 0 ↔ i < 0 ∧ i % j ≠ 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs