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Proof step 2 from proof mod-mult-pos (previous step)

i0 < j, 0 ≤ i, 0 ≤ i0, 0 < j ⊦ (j * i + i0) % j = i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i + j = j + i
Proof step 4:
i0 < j, 0 ≤ i, 0 ≤ i0, 0 < j ⊦ (i0 + j * i) % j = i0

Rule argument

spec: int-basic2 inst: name: add-c seq: ⊦ i + j = j + i subst: [j, i] → [i0, j * i] flags: rewrite

Additional information

Used terms: i0, j * i