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Proof step 7 from proof mod-mult-pos (previous step)

i0 < j, 0 ≤ i, 0 ≤ i0, 0 < j ⊦ i0 % j = i0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-div inst: name: mod-zero-05 seq: ⊦ abs(i) < j → i % j = i subst: [j, i] → [j, i0] flags: rewrite, current

Additional information

Used simplifier rules: absle: ⊦ 0 ≤ i → abs(i) = i; from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs Used terms: j, i0