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Proof step 12 from proof mod-next-square (previous step)

i ≤ 0 ⊦ i % 2 = 0, ((i * i) * (i + 1) * (i + 1)) % 4 = 0, i % 2 ≠ 1 ∧ 0 < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ i % 2 + 1 ≠ 0 ∧ i < 0 → i % 2 = 0
Proof step 14:
¬(i % 2 + 1 ≠ 0 ∧ i < 0), i ≤ 0 ⊦ i % 2 = 0, ((i * i) * (i + 1) * (i + 1)) % 4 = 0, i % 2 ≠ 1 ∧ 0 < i

Rule argument

spec: int-div inst: name: mod-two-01 seq: ⊦ i % 2 + 1 ≠ 0 ∧ i < 0 → i % 2 = 0 subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i