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Proof step 4 from proof mod-next-square (previous step)

⊦ i % 2 = 0, ((i * i) * (i + 1) * (i + 1)) % 4 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ i % 2 ≠ 1 ∧ 0 < i → i % 2 = 0
Proof step 6:
¬(i % 2 ≠ 1 ∧ 0 < i) ⊦ i % 2 = 0, ((i * i) * (i + 1) * (i + 1)) % 4 = 0

Rule argument

spec: int-div inst: name: mod-two seq: ⊦ i % 2 ≠ 1 ∧ 0 < i → i % 2 = 0 subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i