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Proof step 3 from proof mod-nls-02 (previous step)

i % j < 0, i0 < i, i % j < 0, i % j < ~1, i0 < 0, i % j < i0, i0 ≤ i, 0 < i, i0 + 1 < i, abs(j) = 1 ∨ abs(j) ≤ i ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-div inst: name: mod-zero-06 seq: ⊦ 0 ≤ i ∧ j ≠ 0 → ¬ i % j < 0 subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1 Used terms: j, i