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Proof step 17 from proof mod-nls-04 (previous step)

i % j < i0, i0 + abs(j) ≤ 1, abs(j) ≤ abs(i) % abs(j) ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ 0 < j → ¬ j ≤ i % j

Rule argument

spec: int-div inst: name: mod-les seq: ⊦ 0 < j → ¬ j ≤ i % j subst: [i, j] → [abs(i), abs(j)] flags: rewrite, current

Additional information

Used simplifier rules: abs-06: ⊦ 0 < abs(i) ↔ i ≠ 0; from specification int-abs Used terms: abs(i), abs(j)