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Proof step 2 from proof mod-nls-06 (previous step)

i0 < i % j, abs(j) ≤ i0 + 1 ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ j ≤ i0 + 1 ∧ 0 < j → ¬ i0 < i % j
Proof step 4:
¬(j ≤ i0 + 1 ∧ 0 < j), i0 < i % j, abs(j) ≤ i0 + 1 ⊦ j = 0

Rule argument

spec: int-div inst: name: mod-nls-05 seq: ⊦ j ≤ i0 + 1 ∧ 0 < j → ¬ i0 < i % j subst: [j, i, i0] → [j, i, i0] flags: rewrite, current

Additional information

Used terms: j, i, i0