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Proof step 2 from proof mod-sub (
previous step
)
i - j = i + ~ j ⊦ 0 < i ∧ j < 0 → (i - j) % i = ~(j % i)
User applied rule insert equation
And obtained the following new goals
Proof step 3
:
⊦ 0 < i ∧ j < 0 → (i + ~ j) % i = ~(j % i)
Rule argument
pos: left 1 flags: discard
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