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Proof step 1 from proof mod-two-06 (conclusion)

⊦ 0 < i → (i % 2 ≠ 1 ↔ i % 2 = 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ i % 2 ≠ 1 ↔ i % 2 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs