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Proof step 1 from proof mod-two-pred-02 (conclusion)

⊦ i < 0 → (1 - 2 * i) % 2 = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 0 ⊦ (1 - 2 * i) % 2 = 1

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs