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Proof step 3 from proof mod-two-pred-02 (
previous step
)
1 - 2 * i = ~(2 * i - 1), i < 0 ⊦ (1 - 2 * i) % 2 = 1
User applied rule insert equation
And obtained the following new goals
Proof step 4
:
i < 0 ⊦ ~(2 * i - 1) % 2 = 1
Rule argument
pos: left 1 flags: discard
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