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Proof step 2 from proof mod-zero-ls (previous step)

i % j < 0, 0 < j, 0 < i, i % j + 1 < j, j ≤ i, i % j + 1 < i ⊦ j = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < j ∧ 0 ≤ i → ¬ i % j < 0

Rule argument

spec: int-div inst: name: mod-zero-01 seq: ⊦ 0 < j ∧ 0 ≤ i → ¬ i % j < 0 subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1 Used terms: j, i