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Proof step 11 from proof mod-zero-one (previous step)

i0 % j + i % j < 2 * j, i % j < j, i0 % j < j, 0 ≤ i, 0 ≤ i0, 0 < j, 1 < (i % j + i0 % j) / j, 0 < (i % j + i0 % j) / j ⊦ (i % j + i0 % j) / j = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: mod-less-01: ⊦ 0 < j → i % j < j;