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Proof step 3 from proof mod2-add-neg (previous step)

0 < j, j % 2 = 0, abs(i) ≤ j, i ≤ 0 ⊦ i % 2 + (i + j) % 2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j % 2 = 0, abs(i) ≤ j, i ≤ 0, 0 < j, i < j ⊦ i % 2 + (i + j) % 2 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs