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Proof step 1 from proof modby6-help (conclusion)

⊦ (i + 1) * (2 + i) * (2 * (i + 1) + 1) = 6 * (i + 1) * (i + 1) + i * (i + 1) * (2 * i + 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ i * (j + j0) = i * j + i * j0
Proof step 3:
⊦ (i + 1) * (2 + i) * (2 * (i + 1) + 1) = 6 * ((i + 1) * i + (i + 1) * 1) + i * (i + 1) * (2 * i + 1)

Rule argument

spec: int-mult inst: name: dist-rsplit seq: ⊦ i * (j + j0) = i * j + i * j0 subst: [j0, j, i] → [1, i, i + 1] flags: rewrite

Additional information

Used terms: 1, i, i + 1