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Proof step 23 from proof modby6-help (previous step)

⊦ (i + 1) * (6 + 3 * i + 2 * 2 * i + i * 2 * i) = 12 * i + 6 * i * i + 6 + i * (i + 1) * (2 * i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
⊦ (i + 1) * (i * 7 + 6 + i * 2 * i) = 12 * i + 6 * i * i + 6 + i * (i + 1) * (2 * i + 1)

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%numdist: ⊦ i0 * (* i) + i0 * (* j) = i0 * (i + j); from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult