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Proof step 29 from proof modby6-help (previous step)

⊦ ~4 * i * i + ~5 * i + i * i * 7 + i * (6 + i * 2 * i) = i * (i + 1) * (2 * i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
⊦ (i * i) * 3 + ~5 * i + i * (6 + i * 2 * i) = i * (i + 1) * (2 * i + 1)

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%numdist: ⊦ i0 * (* i) + i0 * (* j) = i0 * (i + j); from specification int-mult