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Proof step 35 from proof modby6-help (previous step)

⊦ i + (i * i) * 3 + i * i * 2 * i = i * ((i + 1) * 2 * i + (i + 1) * 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
⊦ i + (i * i) * 3 + i * i * 2 * i = i * ((i + 1) * 2 * i + i + 1)

Rule argument

Additional information

Used simplifier rules: add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%one: ⊦ 1 * i = i; from specification int-mult